Thingiverse link: http://www.thingiverse.com/make:76264
Settings: Printed on a MakerBot Replicator 2 with no supports except for the external support stand that prints along with the model. We printed this one at 120% scale to make it even bigger, but that made the stand thicker also, and therefore more difficult to remove. Next time I'll redo the scaling in OpenSCAD instead, so that I can scale up the Buckyball while making a new stand that preserves its fine grid.
Technical notes, math flavor: The even smaller C60 Buckminsterfullerene has the shape of a soccer ball, with 12 pentagons faces, 20 hexagon faces, and 60 vertices. As a polyhedron it's known as the Truncated Icosahedron, and we printed it on Day 91 with snap-tiles:
In general a Buckyball is just a convex polyhedron made up of regular pentagon and hexagon faces, with each vertex having three edges coming into it. A really cool fact is that every Buckyball has exactly 12 pentagon faces, just like the soccer ball; if you look at the pictures of C320 and C540 you can see that the corner cells of the icosahedral shapes of the models are tiny pentagons, while every other cell is a tiny hexagon.
Here's the classic proof that all Buckyballs have 12 pentagon faces. The proof uses the fact that the Euler characteristic of anything topologically equivalent to a sphere is 2, or in other words, that if a polyhedron has V vertices (corners/points), E edges, and F faces, then
V - E + F = 2.
While that fact is true of all polyhedra (!), we can say more about Buckyballs. In particular, the number F of faces of a Buckyball is the sum of the number of its pentagon faces and the number of its hexagon faces:
F = P + H.
In addition, each pentagon face of a Buckyball has 5 edges surrounding it, and each hexagon face has 6 edges surrounding it. If we calculate 5P+6H we get the total number of edges on the Buckyball, but counting every edge twice - since every edge meets exactly two faces. In other words we have:
E = (5P + 6H)/2.
But there is another way to count the number of edges on a Buckyball: Each vertex has three edges coming into it, which means that 3V counts the number of edges, but again over-counting by a factor of two due to the fact that every edge will be counted by two vertices, one on each of its endpoints. Thus E = (3V)/2, and combining this with the previous equation gives:
V = (5P + 6H)/3.
Putting the three previous centered equations into the Euler characteristic formula gives us:
(5P+6H)/3 - (5P+6H)/2 + (P+H) = 2.
Surprisingly, when you multiply both sides of this equation by 6 to clear fractions and then combine terms, all of the H terms cancel and you are left with:
P = 12.
Therefore every Buckyball has exactly 12 pentagon faces. In a way you can think of Buckyballs as expansions of the 12-pentagon-faced dodecahedron, with hexagons added between the pentagons to make an icosahedral shape with the 12 pentagons at the corners.
